Unit 4 · Lesson 5a

5aMagnetic Fields and Forces

Explore how magnetic fields exert forces on moving charges and current-carrying wires using F = qvB sinθ and the right-hand rule.

Magnetic forces on moving charges underpin electric motors, particle accelerators, MRI machines, and the compass — understanding them connects fundamental physics to modern technology.

Lesson Overview

Magnetic fields exert forces on moving charges and current-carrying wires. In this lesson you will learn how to calculate the magnetic force using F = qvB sinθ and F = BIL sinθ, apply the right-hand rule to determine force direction, and understand how magnetic field lines represent field direction and strength — including Earth's own magnetic field.

Key Concepts

Magnetic Field (B)

A vector field measured in tesla (T) that exerts force on moving charges

Force on a Charge

F = qvB sinθ; maximum when velocity ⊥ field, zero when parallel

Right-Hand Rule

Point fingers in v direction, curl toward B — thumb points in direction of F (positive charge)

Force on a Wire

F = BIL sinθ; depends on current I, length L, and angle θ between wire and B

Magnetic Field Lines

Exit north pole, enter south pole outside magnet; inside magnet S → N

Earth's Magnetic Field

Geographic north ≈ magnetic south pole; field ≈ 25–65 μT at surface

Example 1

A proton (q = 1.6 × 10⁻¹⁹ C) moves at 3.0 × 10⁶ m/s perpendicular to a magnetic field of 0.50 T. Calculate the magnetic force on the proton.

Answer:F = qvB sinθ = (1.6 × 10⁻¹⁹)(3.0 × 10⁶)(0.50)(sin 90°) = 2.4 × 10⁻¹³ N.
Example 2

An electron moves parallel to a magnetic field of 2.0 T at 5.0 × 10⁵ m/s. What is the magnetic force on it?

Answer:F = qvB sinθ = qvB sin 0° = 0 N. When velocity is parallel to B, there is no magnetic force.
Example 3

A wire carries a current of 4.0 A and has a length of 0.30 m in a 0.80 T field perpendicular to the wire. Find the force on the wire.

Answer:F = BIL sinθ = (0.80)(4.0)(0.30)(sin 90°) = 0.96 N.
Example 4

Using the right-hand rule, determine the direction of force on a positive charge moving east in a magnetic field pointing north.

Answer:Point fingers east (v), curl toward north (B) — thumb points upward. The force on the positive charge is directed upward (out of the ground).
Example 5

A wire of length 0.50 m carrying 2.0 A makes a 30° angle with a 1.2 T magnetic field. Calculate the force on the wire.

Answer:F = BIL sinθ = (1.2)(2.0)(0.50)(sin 30°) = (1.2)(2.0)(0.50)(0.5) = 0.60 N.
Guided Problem 1

An alpha particle (q = 3.2 × 10⁻¹⁹ C) moves at 2.0 × 10⁶ m/s at 90° to a 0.40 T field. Find the magnetic force.

Hint: Use F = qvB sinθ with θ = 90°, so sinθ = 1.

Guided Problem 2

A 0.20 m wire carries 5.0 A perpendicular to a magnetic field. The force on the wire is 0.40 N. Find B.

Hint: Rearrange F = BIL sinθ for B. With θ = 90°, B = F / (IL).

Guided Problem 3

A negative charge moves west in a field pointing upward. In which direction is the magnetic force?

Hint: Apply the right-hand rule for a positive charge first, then reverse the direction for a negative charge.

Guided Problem 4

Why do magnetic field lines never cross each other?

Hint: Think about what crossing field lines would imply about the direction of the field at that point.

Guided Problem 5

Earth's magnetic field near the surface is about 50 μT. A wire of length 1.0 m carries 10 A perpendicular to this field. Calculate the force.

Hint: Convert μT to T first (50 μT = 5.0 × 10⁻⁵ T), then use F = BIL.

Key Vocabulary

Magnetic Field (B)

A region of space where a magnetic force acts on moving charges or magnetic materials; measured in tesla (T).

Example: The magnetic field between two bar magnets is strongest near the poles.

Tesla (T)

The SI unit of magnetic field strength; 1 T = 1 N/(A·m).

Example: An MRI machine uses a magnetic field of 1–3 T, far stronger than Earth's field.

Right-Hand Rule

A mnemonic for finding the direction of magnetic force: point fingers in the direction of velocity, curl toward B; thumb points in the direction of force on a positive charge.

Example: Using the right-hand rule, a proton moving east in a northward field experiences an upward force.

Magnetic Force

The force exerted on a moving charge or current-carrying conductor by a magnetic field; F = qvB sinθ or F = BIL sinθ.

Example: The magnetic force causes a current-carrying wire to deflect when placed between magnet poles.

Interactive Practice — 5 Questions

1

What is the SI unit of magnetic field strength?

2

A charge moves parallel to a magnetic field. The magnetic force on it is:

3

Which rule determines the direction of force on a positive charge moving through a magnetic field?

4

A 0.10 m wire carries 3.0 A perpendicular to a 2.0 T field. What is the force on the wire?

5

Outside a bar magnet, magnetic field lines run from:

Independent Practice

1

A proton moves at 4.0 × 10⁶ m/s at 60° to a 0.30 T field. Calculate the magnetic force on it (q = 1.6 × 10⁻¹⁹ C).

2

A wire of length 0.40 m carries 6.0 A at 45° to a 1.5 T magnetic field. Find the force on the wire.

3

Explain why a stationary charge experiences no magnetic force even in a strong magnetic field.

4

Describe the pattern of magnetic field lines around a bar magnet, both inside and outside the magnet.

5

★ A charged particle moves in a circle inside a uniform magnetic field. Derive an expression for the radius of the circular path in terms of m, v, q, and B.

Challenge
⚠️

Common Mistakes

Using F = qvB without including sinθ, giving the wrong answer when v and B are not perpendicular.

Always use F = qvB sinθ; only when θ = 90° does sinθ = 1 and F = qvB.

Thinking magnetic field lines go from south to north outside the magnet.

Field lines exit the north pole and enter the south pole outside; inside the magnet they go from S to N.

Applying the right-hand rule result directly to negative charges.

The right-hand rule gives force direction for positive charges; for negative charges, reverse the direction.

💡

Math Tips

📌

For F = qvB sinθ: identify θ as the angle between the velocity vector and the magnetic field vector — not the angle of the path.

📌

Units check: [T] = [N/(A·m)], so [B][I][L] = [N/(A·m)][A][m] = [N]. ✓