Unit 8 · Chapter 8.6

8.6Understanding Parametric Equations

Graph parametric curves (x(t), y(t)), eliminate the parameter to find the rectangular equation, and model projectile motion with x = v₀cosθ·t and y = v₀sinθ·t − ½gt².

Parametric equations describe motion along a curve — position as a function of time. They are essential for modeling projectile motion, circular motion, and are the foundation for parametric calculus (arc length, velocity vectors).

Essential Question

How do parametric equations x = f(t) and y = g(t) describe a curve differently from a single equation in x and y, and what information do they capture that rectangular equations cannot?

Lesson Overview

Parametric equations define a curve by expressing both x and y as functions of a third variable called the parameter, usually t:

x = f(t),   y = g(t),   t ∈ [a, b]

The parametric curve is the set of all points (f(t), g(t)) as t varies over its interval. Unlike y = f(x), parametric equations can represent curves that loop, cross themselves, or fail the vertical line test.

Direction of travel: as t increases, the curve is traced in a specific direction — this orientation is encoded in the parametric form but lost when converting to a rectangular equation.

Eliminating the parameter: to find the rectangular equation, solve for t in one equation and substitute into the other. For trig forms, use the identity sin²t + cos²t = 1.

Curvex(t)y(t)Rectangular
Linex₀ + aty₀ + bty − y₀ = (b/a)(x − x₀)
Circler cos(t)r sin(t)x² + y² = r²
Ellipsea cos(t)b sin(t)x²/a² + y²/b² = 1
Parabolaty = x²
Parabola (horiz.)tx = y²

Restricting the domain: by limiting the t-interval, parametric equations can represent only a portion of a rectangular curve — for example, just the upper semicircle or a finite line segment.

xy123-1-2-323-2(3, 0)t = 0(0, 2)t = π/2(-3, 0)t = πx²/9 + y²/4 = 1eliminate parameter →x = 3cos(t), y = 2sin(t)
The ellipse traced by x = 3cos(t), y = 2sin(t) as t increases from 0 to 2π (counterclockwise). Eliminating the parameter gives x²/9 + y²/4 = 1.

Worked Examples

Example 1

Sketch the curve x = t − 1, y = t² for −2 ≤ t ≤ 2. Eliminate the parameter.

Make a table: t = −2 → (−3, 4); t = −1 → (−2, 1); t = 0 → (−1, 0); t = 1 → (0, 1); t = 2 → (1, 4).

Plot the points and connect in order of increasing t — the curve moves right as t increases.

Eliminate: from x = t − 1, solve for t: t = x + 1.

Substitute into y = t²: y = (x + 1)².

Domain: t ∈ [−2, 2] → x ∈ [−3, 1], so the rectangular equation is restricted to −3 ≤ x ≤ 1.

Answer:y = (x + 1)², for −3 ≤ x ≤ 1 — a parabola opening upward, vertex at (−1, 0).
Example 2

Eliminate the parameter from x = 3cos(t), y = 2sin(t) and identify the curve.

Isolate the trig functions: cos(t) = x/3, sin(t) = y/2.

Use the Pythagorean identity: cos²(t) + sin²(t) = 1.

Substitute: (x/3)² + (y/2)² = 1.

Simplify: x²/9 + y²/4 = 1.

Answer:x²/9 + y²/4 = 1 — an ellipse with semi-major axis a = 3 along the x-axis and semi-minor axis b = 2 along the y-axis.
Example 3

Write parametric equations for the line through (2, −1) with slope 3.

A line through (x₀, y₀) with slope m = b/a can be parameterized with direction vector ⟨1, m⟩.

Choose a = 1, b = 3 (slope = b/a = 3).

Set x = x₀ + at = 2 + t, y = y₀ + bt = −1 + 3t.

Answer:x = 2 + t, y = −1 + 3t (t ∈ ℝ). Check: eliminating t gives y + 1 = 3(x − 2), i.e., y = 3x − 7. ✓
Example 4

Eliminate the parameter from x = eᵗ, y = e²ᵗ − 1 and identify the curve.

From x = eᵗ, note that eᵗ = x, so e²ᵗ = (eᵗ)² = x².

Substitute into y: y = x² − 1.

Domain restriction: since x = eᵗ {'>'} 0 for all t, we have x {'>'} 0.

Answer:y = x² − 1 for x {'>'} 0 — the right half of a parabola opening upward, vertex at (0, −1) (not included).
Example 5

Write parametric equations for the circle x² + y² = 25, then for only the upper semicircle.

Full circle: use x = r cos(t), y = r sin(t) with r = 5.

Full circle: x = 5cos(t), y = 5sin(t), t ∈ [0, 2π].

Upper semicircle: y ≥ 0 means sin(t) ≥ 0, which holds for t ∈ [0, π].

Upper semicircle: x = 5cos(t), y = 5sin(t), t ∈ [0, π].

Answer:Full circle: x = 5cos(t), y = 5sin(t), t ∈ [0, 2π]. Upper semicircle: same equations with t ∈ [0, π].

Guided Practice

Guided Problem 1

Sketch x = 2t + 1, y = t − 3 for −2 ≤ t ≤ 2. Eliminate the parameter and identify the curve.

Hint: Solve for t from the x-equation: t = (x − 1)/2. Then substitute into y = t − 3.

Guided Problem 2

Eliminate the parameter from x = cos(t), y = sin²(t) and write the rectangular equation.

Hint: Use the identity sin²t = 1 − cos²t, then replace cos(t) with x.

Guided Problem 3

Write parametric equations for the ellipse x²/16 + y²/9 = 1.

Hint: Match to the standard form x = a cos(t), y = b sin(t). Identify a² = 16 and b² = 9.

Guided Problem 4

Eliminate the parameter from x = t², y = t³ and identify any domain restrictions.

Hint: Solve for t from x = t²: t = ±√x. Then substitute into y = t³. Consider which branch applies.

Guided Problem 5

Write parametric equations for the line segment from (1, 2) to (5, 8).

Hint: Use x = x₁ + (x₂ − x₁)t, y = y₁ + (y₂ − y₁)t with t ∈ [0, 1]. At t = 0 you get the start point; at t = 1 you get the end point.

Key Vocabulary

Parametric equations

A pair of equations x = f(t) and y = g(t) that express the coordinates of a point as functions of a third variable t.

Example: x = cos(t), y = sin(t)

Parameter

The independent variable t in parametric equations. It is not necessarily time, though it often represents time in physics applications.

Example: In x = 3t + 1, y = t², the parameter is t.

Parametric curve

The set of all points (f(t), g(t)) traced as t varies over its domain interval.

Direction of travel (orientation)

The direction in which the curve is traced as t increases. This information is lost when converting to a rectangular equation.

Example: x = cos(t), y = sin(t) traces counterclockwise; x = cos(t), y = −sin(t) traces clockwise.

Eliminating the parameter

The process of combining the two parametric equations to produce a single rectangular equation in x and y only.

Example: From x = t + 1, y = t²: t = x − 1, so y = (x − 1)².

Rectangular equation

An equation relating x and y directly, without a parameter. Also called a Cartesian equation.

Example: y = x² − 4x + 3

Check Your Understanding

Interactive Practice — 5 Questions

1

The curve defined by x = cos(t), y = sin(t) for t ∈ [0, 2π] is a:

2

Eliminating the parameter from x = t + 2, y = t² gives:

3

Parametric equations can represent curves that:

4

The parametric equations x = 4cos(t), y = 3sin(t) represent:

5

To eliminate the parameter from x = eᵗ, y = e³ᵗ, the best first step is:

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Common Mistakes

Forgetting the domain restriction when eliminating the parameter — e.g., from x = t², y = t, writing y = √x for all x.

Since x = t² ≥ 0 and y = t can be negative, the correct rectangular form is y = ±√x (or two branches). If t ≥ 0, then y = √x; if t ≤ 0, then y = −√x. Always check the t-interval.

Assuming the parameter t always represents time.

t is just a variable — it can represent time, angle, arc length, or anything else. The label 't' is conventional, not mandatory.

Losing the direction of travel when converting to rectangular form.

The rectangular equation x²/9 + y²/4 = 1 gives the same ellipse whether traced clockwise or counterclockwise. Always note the orientation from the original parametric form.

For x = a cos(t), y = b sin(t), writing the ellipse as x²/b² + y²/a² = 1 (swapping a and b).

Divide correctly: cos(t) = x/a, sin(t) = y/b, so (x/a)² + (y/b)² = 1, giving x²/a² + y²/b² = 1.

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Math Tips

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The three main elimination strategies: (1) solve for t directly (linear/polynomial), (2) use sin²t + cos²t = 1 (trig forms), (3) use eᵗ substitution (exponential forms).

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Parametric equations are more powerful than rectangular equations — they encode direction, speed, and can represent curves that fail the vertical line test.

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For a line through (x₀, y₀) with direction vector ⟨a, b⟩: x = x₀ + at, y = y₀ + bt. The slope of the line is b/a (when a ≠ 0).

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To restrict a curve to a portion, restrict the t-interval. The full circle x = cos(t), y = sin(t) uses t ∈ [0, 2π]; the upper semicircle uses t ∈ [0, π]; the right semicircle uses t ∈ [−π/2, π/2].

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When eliminating the parameter using trig, always look for sin²t + cos²t = 1 — this is the key identity for circles and ellipses. For hyperbolas, use sec²t − tan²t = 1.