Unit 7 · Chapter 7.1

7.1Simplifying and Proving Trigonometric Identities

Apply Pythagorean identities (sin²θ + cos²θ = 1 and variants), reciprocal identities, and quotient identities to simplify trig expressions and prove identities.

Trig identities are the algebraic tools for simplifying and solving trig equations. The Pythagorean, reciprocal, and quotient identities are used in every calculus integration technique involving trig substitution.

How can you use known trigonometric relationships to rewrite an expression in a simpler or more useful form?

A trigonometric identity is an equation that is true for all values of the variable for which both sides are defined. Unlike a conditional equation (which may be true only for specific values), an identity holds universally.

The three families of fundamental identities are:

Pythagorean

sin²θ + cos²θ = 1

1 + tan²θ = sec²θ

1 + cot²θ = csc²θ

Reciprocal

cscθ = 1/sinθ

secθ = 1/cosθ

cotθ = 1/tanθ

Quotient

tanθ = sinθ/cosθ

cotθ = cosθ/sinθ

(cosθ, sinθ)cosθsinθyxsin²θ + cos²θ = 1O

Strategy for proving identities: Work on one side only (usually the more complex side). Rewrite using known identities, factor, combine fractions, or multiply by a conjugate until the two sides match. Never move terms across the equals sign.

Example 1

Simplify: sin²θ · sec²θ + sin²θ

Factor out sin²θ: sin²θ(sec²θ + 1)

Replace sec²θ + 1 using the Pythagorean identity 1 + tan²θ = sec²θ → sec²θ + 1 = tan²θ + 2. Wait — let's try a cleaner approach.

Factor: sin²θ · sec²θ + sin²θ = sin²θ(sec²θ + 1)

Use sec²θ = 1/cos²θ: sin²θ/cos²θ + sin²θ = tan²θ + sin²θ

Alternatively, factor differently: sin²θ(1/cos²θ + 1) = sin²θ · (1 + cos²θ)/cos²θ = tan²θ · (1 + cos²θ) — this doesn't simplify further, so the simplest form is tan²θ + sin²θ.

Answer:tan²θ + sin²θ
Example 2

Simplify: (1 − cos²θ)/sinθ

Recognize 1 − cos²θ = sin²θ (Pythagorean identity).

Substitute: sin²θ / sinθ

Cancel one factor of sinθ (assuming sinθ ≠ 0): sinθ

Answer:sinθ
Example 3

Prove the identity: tanθ · cosθ = sinθ

Start with the left side: tanθ · cosθ

Replace tanθ with sinθ/cosθ (quotient identity): (sinθ/cosθ) · cosθ

Cancel cosθ: sinθ

Left side equals right side. ✓

Answer:Identity proved: tanθ · cosθ = sinθ
Example 4

Prove: secθ − cosθ = sinθ · tanθ

Work on the left side: secθ − cosθ

Replace secθ = 1/cosθ: 1/cosθ − cosθ

Combine over a common denominator: (1 − cos²θ)/cosθ

Use 1 − cos²θ = sin²θ: sin²θ/cosθ

Split: sinθ · (sinθ/cosθ) = sinθ · tanθ ✓

Answer:Identity proved: secθ − cosθ = sinθ · tanθ
Example 5

Simplify: (sec²θ − 1)/sec²θ

Use sec²θ − 1 = tan²θ (Pythagorean identity): tan²θ/sec²θ

Replace sec²θ = 1/cos²θ: tan²θ · cos²θ

Replace tan²θ = sin²θ/cos²θ: (sin²θ/cos²θ) · cos²θ

Cancel cos²θ: sin²θ

Answer:sin²θ
Guided Problem 1

Simplify: cos²θ · csc²θ − cos²θ

Hint: Factor out cos²θ, then use a Pythagorean identity on what remains inside the parentheses.

Guided Problem 2

Simplify: sinθ · cotθ

Hint: Replace cotθ with cosθ/sinθ and cancel.

Guided Problem 3

Prove: cscθ · cosθ = cotθ

Hint: Replace cscθ with 1/sinθ on the left side.

Guided Problem 4

Prove: (1 + tanθ)² = sec²θ + 2tanθ

Hint: Expand the left side, then use 1 + tan²θ = sec²θ.

Guided Problem 5

Simplify: (csc²θ − 1)/csc²θ

Hint: Use csc²θ − 1 = cot²θ, then rewrite cot²θ/csc²θ in terms of sin and cos.

Interactive Practice — 5 Questions

1

Which identity states that sin²θ + cos²θ = 1?

2

Simplify: sinθ/cosθ

3

Which expression is equivalent to 1 − sin²θ?

4

Simplify: cosθ · tanθ

5

To prove an identity, you should:

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Common Mistakes

Moving terms across the equals sign when proving an identity (e.g., adding cosθ to both sides).

Work on one side only. Transform it using identities until it equals the other side.

Confusing sec²θ − 1 = tan²θ with sec²θ + 1 = tan²θ.

The correct form is sec²θ − 1 = tan²θ (subtract 1 from sec²θ = 1 + tan²θ).

Writing 1/sin²θ = cos²θ.

1/sin²θ = csc²θ. The reciprocal of sin²θ is csc²θ, not cos²θ.

Cancelling sinθ from sinθ + cos²θ/sinθ as if sinθ were a factor of the whole expression.

Only cancel common factors. Here sinθ is a term in the numerator, not a factor of the entire numerator.

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Math Tips

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When stuck proving an identity, try converting everything to sinθ and cosθ — it almost always reveals the path.

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The three Pythagorean identities all come from one equation: sin²θ + cos²θ = 1. Divide both sides by cos²θ to get 1 + tan²θ = sec²θ; divide by sin²θ to get cot²θ + 1 = csc²θ.

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If you see a difference of squares like 1 − cos²θ or sec²θ − 1, immediately replace it with the Pythagorean equivalent.

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Multiplying numerator and denominator by a conjugate (e.g., 1 + sinθ) is a powerful technique when you see expressions like 1 − sinθ in a denominator.

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Always check the domain: identities hold wherever both sides are defined. Note that tanθ is undefined at θ = π/2 + nπ.