Unit 5 · Chapter 5.3

5.3Exploring Tangent and the Reciprocal Functions

Define tan θ = sin/cos, cot θ = cos/sin, sec θ = 1/cos, csc θ = 1/sin. Evaluate all six trig functions from the unit circle and identify where each is undefined.

Tangent, secant, cosecant, and cotangent complete the six trig functions. All six appear in calculus derivatives and integrals — knowing their definitions as ratios of sine and cosine makes every trig identity and derivative derivable.

Essential Question

How do tangent, cotangent, secant, and cosecant extend the two basic trig functions — and where do they break down?

Lesson Overview

Sine and cosine describe the y- and x-coordinates of a point on the unit circle. The other four trig functions are built entirely from those two ratios. Tangent is the slope of the terminal side; cotangent is its reciprocal. Secant and cosecant are the reciprocals of cosine and sine. Because they involve division, each function is undefined whenever its denominator equals zero — producing vertical asymptotes in their graphs.

All Six Trig Functions at a Glance

The Six Trigonometric FunctionsFunctionUnit CircleRight Trianglesin θy / ropposite / hypotenusecos θx / radjacent / hypotenusetan θy / xopposite / adjacentcsc θr / yhypotenuse / oppositesec θr / xhypotenuse / adjacentcot θx / yadjacent / oppositer = 1 on the unit circle, so sin θ = y and cos θ = x

Geometric Meaning of Tangent

Geometric Meaning of tan θ(cos θ, sin θ)(1, 0)tan θθ−111−1tan θ = sin θ / cos θ = length of red segment when r = 1

When the unit circle is drawn with a vertical tangent line at (1, 0), the length of the segment from (1, 0) to where the terminal side meets that line equals tan θ.

Where Each Function Is Undefined

Where Are the Functions Undefined?FunctionUndefined when…Key angles (radians)tan θcos θ = 0π/2, 3π/2, …sec θcos θ = 0π/2, 3π/2, …cot θsin θ = 00, π, 2π, …csc θsin θ = 00, π, 2π, …

Pythagorean Identities

Pythagorean IdentitiesFUNDAMENTALsin²θ + cos²θ = 1Divide by cos²θ →TANGENT FORM1 + tan²θ = sec²θDivide by sin²θ →COTANGENT FORM1 + cot²θ = csc²θ

Divide sin²θ + cos²θ = 1 by cos²θ to get the tangent form; divide by sin²θ to get the cotangent form.

Signs in Each Quadrant

Signs of All Six Functions by QuadrantQIIsin +cos −tan −csc +sec −cot −QIsin +cos +tan +csc +sec +cot +QIIIsin −cos −tan +csc −sec −cot +QIVsin −cos +tan −csc −sec +cot −Mnemonic: All Students Take Calculus (QI→QII→QIII→QIV: All, Sin, Tan, Cos positive)

Key Vocabulary

Tangent (tan θ)

tan θ = sin θ / cos θ = y/x. Undefined when cos θ = 0 (i.e., at π/2 + nπ).

Example: tan(π/4) = 1

Cotangent (cot θ)

cot θ = cos θ / sin θ = x/y. Undefined when sin θ = 0 (i.e., at nπ).

Example: cot(π/4) = 1

Secant (sec θ)

sec θ = 1 / cos θ = r/x. Undefined when cos θ = 0.

Example: sec(π/3) = 2

Cosecant (csc θ)

csc θ = 1 / sin θ = r/y. Undefined when sin θ = 0.

Example: csc(π/6) = 2

Reciprocal identity

Each of csc, sec, cot is the reciprocal of sin, cos, tan respectively.

Quotient identity

tan θ = sin θ / cos θ and cot θ = cos θ / sin θ express tan and cot as quotients.

Worked Examples

Example 1

Find all six trig functions for the point (3/5, 4/5) on the unit circle.

Since the point is on the unit circle, r = 1, x = 3/5, y = 4/5.

sin θ = y = 4/5, cos θ = x = 3/5

tan θ = y/x = (4/5)/(3/5) = 4/3

csc θ = 1/sin θ = 5/4, sec θ = 1/cos θ = 5/3

cot θ = 1/tan θ = 3/4

Answer:sin = 4/5, cos = 3/5, tan = 4/3, csc = 5/4, sec = 5/3, cot = 3/4
Example 2

Evaluate all six trig functions at θ = π/6 (30°).

Unit circle: (cos π/6, sin π/6) = (√3/2, 1/2)

sin π/6 = 1/2, cos π/6 = √3/2

tan π/6 = (1/2)/(√3/2) = 1/√3 = √3/3

csc π/6 = 2, sec π/6 = 2/√3 = 2√3/3

cot π/6 = √3

Answer:sin=1/2, cos=√3/2, tan=√3/3, csc=2, sec=2√3/3, cot=√3
Example 3

Use a Pythagorean identity: if tan θ = 2 and θ is in QI, find sec θ.

Identity: 1 + tan²θ = sec²θ

1 + (2)² = sec²θ

1 + 4 = sec²θ → sec²θ = 5

sec θ = √5 (positive because θ is in QI)

Answer:sec θ = √5
Example 4

Determine the sign of cot(5π/4).

5π/4 is in QIII (between π and 3π/2).

cot θ = cos θ / sin θ = (−)/(−) = positive.

Answer:cot(5π/4) > 0 (positive in QIII)
Example 5

Find csc θ if sin θ = −√2/2 and θ is in QIII.

csc θ = 1 / sin θ

csc θ = 1 / (−√2/2) = −2/√2 = −√2

Answer:csc θ = −√2

Guided Practice

Guided Problem 1

The point (−5/13, 12/13) is on the unit circle. Find tan θ and cot θ.

Hint: tan θ = y/x. Substitute x = −5/13 and y = 12/13 directly.

Guided Problem 2

Evaluate sec(π/4) and csc(π/4).

Hint: cos(π/4) = sin(π/4) = √2/2. Take reciprocals.

Guided Problem 3

If cot θ = −3/4 and sin θ {'>'} 0, find csc θ using 1 + cot²θ = csc²θ.

Hint: Square cot θ, add 1, then take the square root. Use the sign of sin θ to choose + or −.

Guided Problem 4

In which quadrant is θ if tan θ {'<'} 0 and sec θ {'>'} 0?

Hint: sec θ {'>'} 0 means cos θ {'>'} 0. tan θ {'<'} 0 with cos θ {'>'} 0 means sin θ {'<'} 0. Which quadrant has cos + and sin −?

Guided Problem 5

Evaluate tan(3π/2). Is it defined? Explain.

Hint: cos(3π/2) = 0. What happens when you divide by zero?

Check Your Understanding

Interactive Practice — 5 Questions

1

Which expression equals tan θ?

2

At which angle is tan θ undefined?

3

Which Pythagorean identity involves sec θ?

4

In QII, which of the following is positive?

5

If cos θ = 1/3, what is sec θ?

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Common Mistakes

Writing csc θ = 1/tan θ (confusing cosecant with cotangent).

csc θ = 1/sin θ and cot θ = 1/tan θ. Cosecant is the reciprocal of sine.

Saying tan(π/2) = 0 because "it looks like a right angle."

tan(π/2) is undefined — cos(π/2) = 0 and division by zero is undefined.

Forgetting to check the quadrant when taking a square root in a Pythagorean identity.

After sec²θ = 5, decide sec θ = +√5 or −√5 based on which quadrant θ is in.

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Math Tips

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The reciprocal pairs are: sin↔csc, cos↔sec, tan↔cot. Their product always equals 1.

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tan θ is the slope of the terminal side of angle θ in standard position.

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Period of tan and cot is π. Period of sec and csc is 2π — same as sin and cos.

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Mnemonic for positive functions by quadrant: "All Students Take Calculus" (QI→QII→QIII→QIV).