Unit 10 · Chapter 10.3

10.3Exploring Parabolas

Write parabola equations x² = 4py (vertical) and y² = 4px (horizontal) using the focus-directrix definition. Identify vertex, focus, directrix, and axis of symmetry. Apply the reflective property.

The parabola's reflective property — all rays parallel to the axis reflect through the focus — is used in satellite dishes, headlights, and solar collectors. The focus-directrix definition unifies the conic section family.

Essential Question

How does the focus-directrix definition of a parabola lead to the standard form equation, and how does the value of p determine the shape and direction of the parabola?

Lesson Overview

directrixV (0,0)F (0,p)ppPPF = PDaxis of symmetry

Definition

A parabola is the set of all points equidistant from a fixed point (the focus) and a fixed line (the directrix).

Standard Forms — Vertex at Origin

DirectionEquationFocusDirectrix
Opens up (p > 0)x² = 4py(0, p)y = −p
Opens down (p > 0)x² = −4py(0, −p)y = p
Opens right (p > 0)y² = 4px(p, 0)x = −p
Opens left (p > 0)y² = −4px(−p, 0)x = p

Standard Forms — Vertex at (h, k)

TypeEquationFocusDirectrix
Vertical(x−h)² = 4p(y−k)(h, k+p)y = k−p
Horizontal(y−k)² = 4p(x−h)(h+p, k)x = h−p
  • Latus rectum: chord through focus perpendicular to axis; length = |4p|
  • p > 0: opens up/right; p < 0: opens down/left
  • Axis of symmetry: line through vertex and focus

Worked Examples

Example 1

Identify all features of x² = 12y.

Form: x² = 4py → 4p = 12 → p = 3

Opens upward (p > 0)

Vertex: (0,0); Focus: (0,3); Directrix: y = −3

Axis of symmetry: x = 0; Latus rectum length: |4p| = 12

Answer:Vertex (0,0), focus (0,3), directrix y=−3, opens up
Example 2

Write the equation of a parabola with vertex (0,0) and focus (−4, 0).

Focus on x-axis → horizontal parabola

p = −4 (negative → opens left)

Form: y² = 4px = 4(−4)x = −16x

Answer:y² = −16x
Example 3

Find all features of (x−2)² = 8(y+1).

Vertex: (2, −1); 4p = 8 → p = 2

Opens upward

Focus: (2, −1+2) = (2, 1)

Directrix: y = −1−2 = −3

Axis of symmetry: x = 2

Answer:Vertex (2,−1), focus (2,1), directrix y=−3
Example 4

Write the equation of a parabola with vertex (3, −2) and directrix x = 1.

Directrix is vertical → horizontal parabola

Distance from vertex to directrix: |3−1| = 2 → p = 2 (opens right, since focus is to the right)

Form: (y−(−2))² = 4(2)(x−3) → (y+2)² = 8(x−3)

Answer:(y+2)² = 8(x−3)
Example 5

Convert y² − 6y − 8x + 1 = 0 to standard form.

Isolate y terms: y² − 6y = 8x − 1

Complete the square: (y−3)² − 9 = 8x − 1

(y−3)² = 8x + 8 = 8(x+1)

Vertex: (−1, 3); 4p = 8 → p = 2

Opens right; Focus: (1, 3); Directrix: x = −3

Answer:(y−3)² = 8(x+1); vertex (−1,3), focus (1,3), directrix x=−3

Guided Practice

Guided Problem 1

Identify all features of y² = −20x.

Hint: Form y² = 4px with 4p = −20. Negative p means opens left.

Guided Problem 2

Write the equation of a parabola with vertex (0,0) and directrix y = 5.

Hint: Directrix y = 5 is above the vertex → parabola opens downward. p = −5.

Guided Problem 3

Find all features of (y+4)² = −12(x−1).

Hint: Horizontal parabola. 4p = −12 → p = −3. Opens left.

Guided Problem 4

Write the equation of a parabola with focus (2, 3) and directrix y = −1.

Hint: Vertex is midpoint between focus and directrix: y-coordinate = (3+(−1))/2 = 1. p = 3−1 = 2.

Guided Problem 5

Convert x² + 4x − 8y + 20 = 0 to standard form.

Hint: Complete the square for x: (x+2)² = 8y − 16 = 8(y−2).

Key Vocabulary

Parabola

Set of all points equidistant from the focus and the directrix.

Focus

The fixed point inside the parabola; distance p from vertex.

Directrix

The fixed line outside the parabola; distance p from vertex on the opposite side.

Vertex

The point on the parabola closest to the directrix; midpoint between focus and directrix.

Axis of symmetry

The line through the vertex and focus; the parabola is symmetric about this line.

p value

The directed distance from vertex to focus; p > 0 opens up/right, p < 0 opens down/left.

Latus rectum

The chord through the focus perpendicular to the axis; length = |4p|.

Standard form

(x−h)² = 4p(y−k) (vertical) or (y−k)² = 4p(x−h) (horizontal).

Practice Quiz

Interactive Practice — 5 Questions

1

For x² = −8y, the focus is at:

2

A parabola has vertex (0,0) and focus (0, 5). Its equation is:

3

For (x−3)² = −12(y+1), the directrix is:

4

The latus rectum length of y² = 16x is:

5

Which parabola opens to the left?

Independent Practice

Independent Practice

1

Find all features of x² = −24y.

2

Write the equation: vertex (0,0), focus (6, 0).

3

Find all features of (x+3)² = 16(y−2).

4

Write the equation: vertex (−1, 4), directrix x = −4.

5

Convert x² − 10x − 4y + 29 = 0 to standard form.

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Common Mistakes

Confusing the sign of p with the direction of opening

p > 0 opens up (vertical) or right (horizontal). p < 0 opens down (vertical) or left (horizontal). The sign of p tells you the direction.

Placing the focus and directrix on the same side of the vertex

The focus is INSIDE the parabola; the directrix is OUTSIDE. They are on OPPOSITE sides of the vertex, each at distance |p|.

Using the wrong form for horizontal vs. vertical parabolas

If x is squared → vertical parabola (opens up/down). If y is squared → horizontal parabola (opens left/right).

Forgetting to divide by 4 to find p from the equation x² = 4py

Always write the equation as x² = 4py first, then p = (coefficient)/4. Don't confuse 4p with p.

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Math Tips

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Quick identification: x² → vertical parabola; y² → horizontal parabola.

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The vertex is always the midpoint between the focus and the directrix.

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Latus rectum = |4p|. A wider parabola has a larger |p|; a narrower one has a smaller |p|.

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To find p from standard form: 4p = coefficient of the linear term. Then p = coefficient/4.

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When completing the square for a parabola, move the linear term to the right side FIRST, then complete the square on the quadratic side.