Unit 0 · Foundations of Geometry

Coordinate Geometry Foundations

Coordinate geometry uses points, slopes, distances, and midpoints to describe geometric figures. Equal slopes identify parallel lines, negative reciprocal slopes identify perpendicular lines, and matching slopes can show that points are collinear.

Coordinate methods turn geometric relationships into calculations that can be checked and explained precisely.

Essential Question

How can coordinates and slope be used to describe geometric relationships?

Learning Goals

  • 1Read and plot ordered pairs on the coordinate plane.
  • 2Identify the quadrant or axis containing a point.
  • 3Find the slope between two points.
  • 4Classify slope as positive, negative, zero, or undefined.
  • 5Determine whether two lines are parallel from their slopes.
  • 6Determine whether two lines are perpendicular from their slopes.
  • 7Use slope to determine whether three points are collinear.

Key Vocabulary

Coordinate plane

A plane formed by a horizontal x-axis and vertical y-axis.

Ordered pair

A pair of numbers written as (x, y) that locates a point.

Origin

The point (0, 0), where the axes intersect.

Quadrant

One of the four regions formed by the x-axis and y-axis.

x-axis

The horizontal axis of the coordinate plane.

y-axis

The vertical axis of the coordinate plane.

Slope

The ratio of vertical change to horizontal change between two points.

Rise

The vertical change between two points.

Run

The horizontal change between two points.

Parallel lines

Coplanar lines that never intersect and have equal slopes when both slopes are defined.

Perpendicular lines

Lines that intersect at right angles and usually have negative reciprocal slopes.

Collinear points

Points that lie on the same line.

Key Ideas

Coordinate geometry uses the coordinate plane to describe geometric figures precisely. Slope measures steepness and direction. Equal slopes identify parallel lines; negative reciprocal slopes identify perpendicular lines; matching slopes through a shared point identify collinear points.

A. Reading Ordered Pairs

  • Coordinates are written (x, y).
  • Move horizontally first (x), then vertically (y).
  • The x-coordinate comes first; the y-coordinate comes second.
  • A point on an axis is not in a quadrant.
xy0-4-3-2-11234-4-3-2-11234A(−4,3)B(2,4)C(3,−2)D(−3,−3)E(0,2)F(−2,0)
Points in all four quadrants and on the axes

B. Quadrants and Axes

  • Quadrant I: (+, +) — right and up
  • Quadrant II: (−, +) — left and up
  • Quadrant III: (−, −) — left and down
  • Quadrant IV: (+, −) — right and down
  • Points with y = 0 lie on the x-axis.
  • Points with x = 0 lie on the y-axis.
xy0-4-3-2-11234-4-3-2-11234I (+,+)II (−,+)III (−,−)IV (+,−)(2,3)(−3,2)(−2,−3)(3,−1)
The four quadrants and their sign patterns

C. Slope Formula

m = (y₂ − y₁) / (x₂ − x₁)

  • Pair y-values with y-values in the numerator.
  • Pair x-values with x-values in the denominator.
  • Use the same subtraction order in both numerator and denominator.
  • Simplify the ratio to lowest terms.
  • Use parentheses around negative coordinates: (−2), not −2.

D. Types of Slope

  • Positive slope: line rises from left to right.
  • Negative slope: line falls from left to right.
  • Zero slope: horizontal line (rise = 0).
  • Undefined slope: vertical line (run = 0; division by zero).
xy0-4-3-2-11234-3-2-1123run=2rise=1m=½ ↗run=2rise=−1m=−½ ↘
Positive slope rises left to right; negative slope falls left to right
xy0-4-3-2-11234-3-2-1123slope = 0(horizontal)slopeundefined(vertical)
Horizontal lines have slope 0; vertical lines have undefined slope

E. Parallel Lines

  • Distinct nonvertical parallel lines have equal slopes.
  • Two distinct vertical lines are also parallel (both have undefined slope).
  • Equal slope alone may describe the same line — distinctness matters.
xy0-4-3-2-11234-3-2-11232121m=½m=½Equal slopes → parallel lines
Parallel lines have equal slopes

F. Perpendicular Lines

  • For nonvertical and nonhorizontal lines, perpendicular slopes are negative reciprocals.
  • Their product equals −1: m₁ · m₂ = −1.
  • A horizontal line and a vertical line are perpendicular to each other.
  • Do not apply the negative-reciprocal rule when one slope is 0 or undefined.
xy0-4-3-2-11234-4-3-2-11234m=⅔m=−³⁄₂(⅔)(−³⁄₂) = −1 → perpendicular
Perpendicular lines have negative reciprocal slopes; product = −1

G. Collinear Points

  • Three points are collinear if they lie on the same line.
  • Compare the slope between one pair with the slope between another pair that shares a point.
  • Use consistent coordinate order in both slope calculations.
  • Matching slopes through a shared point support collinearity.
xy12345246810run=2rise=4A(1,2)B(3,6)C(5,10)slope AB = slope BC = 2 → collinear
A, B, and C are collinear — equal slopes through shared point B

H. Coordinate Reasoning

  1. Identify the geometric relationship being tested.
  2. Choose the correct coordinate tool (slope, distance, or midpoint).
  3. Calculate carefully using consistent order and parentheses.
  4. Interpret the result geometrically.
  5. State a conclusion using precise vocabulary.

Equal slopes

Parallel (or same line)

Negative reciprocal slopes

Perpendicular

Equal slopes + shared point

Collinear

Worked Examples

Example 1 — Identify a Quadrant

Problem: In which quadrant does A(−4, 3) lie?

xy0-4-3-2-11234-4-3-2-11234I (+,+)II (−,+)III (−,−)IV (+,−)(2,3)(−3,2)(−2,−3)(3,−1)
The four quadrants and their sign patterns
  1. Read the x-coordinate: −4. It is negative, so the point is to the left of the y-axis.
  2. Read the y-coordinate: 3. It is positive, so the point is above the x-axis.
  3. The sign pattern (−, +) matches Quadrant II.
Conclusion: A(−4, 3) is in Quadrant II.

Check: Quadrant II contains all points with negative x and positive y. ✓

Example 2 — Find Slope Between Two Points

Problem: Find the slope of the line through B(−2, 1) and C(4, 4).

xy0-4-3-2-11234-3-2-1123run=2rise=1m=½ ↗run=2rise=−1m=−½ ↘
Positive slope rises left to right; negative slope falls left to right
  1. Label the points: (x₁, y₁) = (−2, 1) and (x₂, y₂) = (4, 4).
  2. Apply the slope formula: m = (y₂ − y₁) / (x₂ − x₁)
  3. Substitute: m = (4 − 1) / (4 − (−2))
  4. Simplify the numerator: 4 − 1 = 3
  5. Simplify the denominator: 4 − (−2) = 4 + 2 = 6
  6. Simplify the fraction: m = 3/6 = 1/2
Conclusion: The slope is m = 1/2. The line rises 1 unit for every 2 units of horizontal movement.

Note: Parentheses around (−2) prevent the sign error 4 − −2 = 2.

Example 3 — Zero and Undefined Slope

Problem: Find the slope of each line and classify it.

xy0-4-3-2-11234-3-2-1123slope = 0(horizontal)slopeundefined(vertical)
Horizontal lines have slope 0; vertical lines have undefined slope

Part A — Horizontal line through D(−3, 5) and E(4, 5):

  1. m = (5 − 5) / (4 − (−3)) = 0 / 7 = 0
  2. The numerator is 0; the line is horizontal.

Part B — Vertical line through F(2, −1) and G(2, 6):

  1. m = (6 − (−1)) / (2 − 2) = 7 / 0 = undefined
  2. The denominator is 0; division by zero is undefined. The line is vertical.
Conclusion: Horizontal lines have slope 0. Vertical lines have undefined slope.
Example 4 — Parallel or Perpendicular

Problem: Two lines have slopes m₁ = 2/3 and m₂ = −3/2. Are they parallel, perpendicular, or neither?

xy0-4-3-2-11234-4-3-2-11234m=⅔m=−³⁄₂(⅔)(−³⁄₂) = −1 → perpendicular
Perpendicular lines have negative reciprocal slopes; product = −1
  1. Check for equal slopes: 2/3 ≠ −3/2, so the lines are not parallel.
  2. Check the product: (2/3)(−3/2) = −6/6 = −1.
  3. A product of −1 means the slopes are negative reciprocals.
Conclusion: The lines are perpendicular because their slopes are negative reciprocals and (2/3)(−3/2) = −1.
Example 5 — Test Collinearity

Problem: Are A(1, 2), B(3, 6), and C(5, 10) collinear?

xy12345246810run=2rise=4A(1,2)B(3,6)C(5,10)slope AB = slope BC = 2 → collinear
A, B, and C are collinear — equal slopes through shared point B
  1. Find slope AB: m = (6 − 2) / (3 − 1) = 4 / 2 = 2
  2. Find slope BC: m = (10 − 6) / (5 − 3) = 4 / 2 = 2
  3. Both slopes equal 2, and the segments share point B.
Conclusion: A, B, and C are collinear because slope AB = slope BC = 2 and the segments share point B.

Note: Always check two pairs of slopes that share a common point.

Multiple Choice Check

Question 1

In which quadrant does the point (−5, −2) lie?

xy0-4-3-2-11234-4-3-2-11234I (+,+)II (−,+)III (−,−)IV (+,−)(2,3)(−3,2)(−2,−3)(3,−1)
The four quadrants and their sign patterns
  • AQuadrant I
  • BQuadrant II
  • CQuadrant III
  • DQuadrant IV
Answer:
Question 2

What is the slope of the line through P(1, −3) and Q(5, 5)?

xy0-4-3-2-11234-4-3-2-11234m=2Slope from two points
Slope from two points: m=2 and
  • Am = 1/2
  • Bm = 2
  • Cm = −2
  • Dm = 8/4 = 2 (same as B — distractor: wrong sign)
Answer:
Question 3

A line passes through (−2, 4) and (6, 4). What type of slope does it have?

xy0-4-3-2-11234-3-2-1123slope = 0(horizontal)slopeundefined(vertical)
Horizontal lines have slope 0; vertical lines have undefined slope
  • APositive slope
  • BNegative slope
  • CZero slope
  • DUndefined slope
Answer:
Question 4

Line ℓ has slope 3/4. Line k has slope −4/3. What is the relationship between the lines?

xy0-4-3-2-11234-4-3-2-11234m=⅔m=−³⁄₂(⅔)(−³⁄₂) = −1 → perpendicular
Perpendicular lines have negative reciprocal slopes; product = −1
  • AParallel
  • BPerpendicular
  • CNeither parallel nor perpendicular
  • DThe same line
Answer:
Question 5

Are the points R(0, 0), S(2, 3), and T(4, 6) collinear?

xy12345246810run=2rise=4A(1,2)B(3,6)C(5,10)slope AB = slope BC = 2 → collinear
A, B, and C are collinear — equal slopes through shared point B
  • AYes, because slope RS = slope ST = 3/2 and the segments share point S.
  • BNo, because the slopes are different.
  • CYes, but only because all three points are in Quadrant I.
  • DCannot be determined without the distance formula.
Answer:

Guided Practice

1

Plot the point K(−3, 4) on the coordinate plane. State its quadrant.

xy0-4-3-2-11234-4-3-2-11234A(−4,3)B(2,4)C(3,−2)D(−3,−3)E(0,2)F(−2,0)
Points in all four quadrants and on the axes
2

Find the slope of the line through M(−1, 5) and N(3, −3).

3

A line passes through (4, 7) and (4, −2). Classify the slope as positive, negative, zero, or undefined.

xy0-4-3-2-11234-3-2-1123slope = 0(horizontal)slopeundefined(vertical)
Horizontal lines have slope 0; vertical lines have undefined slope
4

Line j has slope 5/2. Line k has slope 5/2. Line p has slope −2/5. Determine the relationship between each pair: j and k, j and p.

xy0-4-3-2-11234-3-2-11232121m=½m=½Equal slopes → parallel lines
Parallel lines have equal slopes
5

Are the points X(−2, 1), Y(0, 4), and Z(2, 7) collinear? Show your work.

xy12345246810run=2rise=4A(1,2)B(3,6)C(5,10)slope AB = slope BC = 2 → collinear
A, B, and C are collinear — equal slopes through shared point B

Common Mistakes

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Common Mistakes

Reading the ordered pair as (y, x) instead of (x, y)

Always read the horizontal coordinate first: (x, y). Move right/left first, then up/down.

Placing a point in the wrong quadrant by misreading the sign pattern

Quadrant I: (+,+); II: (−,+); III: (−,−); IV: (+,−). Check both signs before plotting.

Saying a point on the x-axis or y-axis is in a quadrant

Points on an axis are not in any quadrant. Quadrants are the open regions between the axes.

Using inconsistent subtraction order in the slope formula

If you compute y₂ − y₁ in the numerator, you must compute x₂ − x₁ in the denominator. Mixing orders gives the wrong sign.

Subtracting x-values in the numerator instead of the denominator

Rise (numerator) uses y-values: y₂ − y₁. Run (denominator) uses x-values: x₂ − x₁.

Forgetting parentheses around a negative coordinate in the slope formula

Write (x₂ − (−3)) = x₂ + 3, not x₂ − −3. Parentheses prevent sign errors.

Calling a horizontal line's slope "undefined"

A horizontal line has slope 0 (rise = 0, run ≠ 0). Undefined slope belongs to vertical lines.

Calling a vertical line's slope "zero"

A vertical line has undefined slope (run = 0, division by zero). Zero slope belongs to horizontal lines.

Assuming two lines are parallel because they look parallel in a diagram

Calculate both slopes and verify they are equal. Visual appearance is not a proof.

Forgetting the negative sign when finding the negative reciprocal

The negative reciprocal of 3/4 is −4/3, not 4/3. Both the flip and the sign change are required.

Applying the product −1 rule to a horizontal and vertical line

Horizontal lines (slope 0) and vertical lines (undefined slope) are perpendicular, but their product is not −1. The negative-reciprocal rule only applies to nonvertical, nonhorizontal lines.

Declaring three points collinear after checking only one slope

Check two slopes that share a common point. One slope only shows two of the three points are connected.

Comparing slopes using inconsistent point order across the two calculations

Use the same labeling convention for both slope calculations. Mixing point order can produce equal slopes by coincidence.

Finding a slope value but failing to state the geometric conclusion

Always interpret the slope result: state whether the lines are parallel, perpendicular, or neither, or whether the points are collinear.

Before You Finish

Key Takeaways

  • Ordered pairs are written (x, y).
  • Quadrants follow specific sign patterns: I(+,+), II(−,+), III(−,−), IV(+,−).
  • Points on axes are not in quadrants.
  • Slope is vertical change divided by horizontal change: m = (y₂−y₁)/(x₂−x₁).
  • Horizontal lines have slope 0.
  • Vertical lines have undefined slope.
  • Parallel lines have equal slopes.
  • Perpendicular nonvertical lines have negative reciprocal slopes.
  • Horizontal and vertical lines are perpendicular.
  • Matching slopes through a shared point can show that points are collinear.

Check Your Understanding

1

Why must the subtraction order be consistent in both parts of the slope formula?

2

How can slopes be used to distinguish parallel lines from perpendicular lines?

3

How can slope be used to show that three points are collinear?